# Compute hamming distance of byte arrays in Scala

Hamming distance is the number of positions in which two different strings are different.

So the distance between both strings would be:

- “ab
**c**de” and “ab**e**de” - 1 - “
**m**o**m**o**m**o” and “**n**o**n**o**n**o” - 3

Implementing this would not be difficult:

```
def hammingDistance(s1: String, s2: String): Int = s1.zip(s2).count(c => c._1 != c._2)
```

Basically you zip (`"abc".zip("bcd")`

produces `scala.collection.immutable.IndexedSeq[(Char, Char)] = Vector((a,b), (b,d), (c,e))`

) strings together and compare corresponding characters. Simple, right?

However, the task I was working on required comparing individual bits, which are slightly more tricky to get to. I couldn’t find quickly any public snippets that do this, so I wrote my own:

true

To get the number of different bits of two bytes we only need to XOR them and compute how many bits are set:

For example: `0b10010101 XOR 0b01011101 = 0b11001000`

.

To calculate the number of bits set we just shift the XORed byte `i`

number of times and `AND 1`

to get rid of other bits.

This method has a performance flaw as it shifts i times for each bit as opposed to shifting once per bit and relying on previous results, but oh well - it’s suitable when high performance is not necessary.

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